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A ball is thrown vertically upward from the top of a 100 foot tower, with an initial velocity of 10 ft/sec. Its position function is s(t) = –16t2 + 10t + 100. What is its velocity in ft/sec when t = 2 seconds?
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find v'(t) and then evaluate v'(t) at t=2
So v'(t) = -32t +10
ooops sorry should have said s'(t)
but yeah v(t)=s'(t) which is the velocity function
but yeah v(t)=-32t+10
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Either way.. I see what I did wrong. I did the same thing but read 10 as 100. Made a completely different answer. Thank you nonetheless
np
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