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A rectangle room is three times as long as it is wide and it perimeter is 56 m find the width of the room
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\[3l=w \]
l represents length and w represents width. Therefore, the length w is 3 times bigger than the length. The equation for perimeter is \[P=2l+2w\]
Now just plug in the value for w in terms of l and it looks like this: \[P = 2l+2(3l)\]
Now remember that the given perimeter was 56m so setting P = 56 m, you get: \[56 = 2l+6l\]
now solve for l which is \[56 = 8l \rightarrow l=56/8\rightarrow 7\]
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you know that 3 times the length is the width, therefore, knowing the length, 3 times 7 is 21 and 21 is the width of the rectangle.
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