Question

A container has 50 electronic components, of which 10 are defective.
If 6 components are drawn at random from the container, what is the probability that at least 4 are good?

0.26
0.42
0.75
0.91
1.00

Answer 1

A

If 4 are good, 2 must be defective.
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Binomial with n = 6 and p(defective) = 1/5
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P(x = 2) = 6C2*(1/5)^2*(4/5)^4 = binompdf(6,1/5,2) = 0.2458
=

Answer 2

thanks for helping me out i suck in geometry