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Mathematics 22 Online
OpenStudy (anonymous):

Factor 360t + 10t 3 - 120t 2.

OpenStudy (anonymous):

150t :) Medal?

OpenStudy (anonymous):

The first answer is completely wrong. You need to simplify, then factor. First, rewrite the equation into an easier form to work with. \[10t^3-120t^2+360t\] We can now extract common terms. \[10t(t^2-12t+36)\] Now, factor. 10t(t-6)(t-6) = \[10t(t-6)^2\] To get 0, x must equal 6.

OpenStudy (anonymous):

Roots= 0 and 6

OpenStudy (anonymous):

I assumed 10t 3 was 10t x 3 and 120 t 2 was 120t x 2; the student didn't specify. @stel.la

OpenStudy (anonymous):

But if it is 10t^3 and 120t^2 then yes, 10t( t- 6)^2 t, would be the answer

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