Question

A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ .

5
√(13)
√(97)

Answer 1

@perl can you please help??

Answer 2

one moment

Answer 3

Thank you!!

Answer 4

I plotted the points here

Answer 5

thats the short diagonal http://prntscr.com/7izzgt

Answer 6

So would it be 5?

Answer 7

we want the distance between (3,3) and (6,1)
distance = \( \sqrt{ (6-3)^2 + (1-3)^2} = \sqrt{ 9 + 4} = \sqrt{13}\)

Answer 8

Ugh. I did it wrong, Thank you for helping me!
If I have any more can you help me?

Answer 9

ok :)