Logarithms Algebra 2

Ashley solved the exponential equation 3x+1 = 15 and her work is shown below. What is the first step she did incorrectly?

Step 1: log 3^(x+1) = log15
Step 2: (x + 1)log 3 = log15
Step 3: x + 1 = log 15/log 3
Step 4: x+1 = 2.708050/1.098612
Step 5: x + 1 = 1.418858
Step 6: x = 0.418858

Question

Logarithms Algebra 2

Ashley solved the exponential equation 3x+1 = 15 and her work is shown below. What is the first step she did incorrectly?

Step 1: log 3^(x+1) = log15
Step 2: (x + 1)log 3 = log15
Step 3: x + 1 = log 15/log 3
Step 4: x+1 = 2.708050/1.098612
Step 5: x + 1 = 1.418858
Step 6: x = 0.418858

debbieg · Answer

Well, obviously $$2.708050/1.098612 \neq1.418858$$(you can see that without even checking it in a calculator, right?)
I don't see anything up to that point that is wrong (although the use of "log" when actually using "ln" is a bit confusing....).