A system of equations is shown below:
Equation A: 2c = d − 8
Equation B: c = 3d + 8
Which of the following steps should be performed to eliminate variable d first?
Multiply equation B by 2.
Multiply equation A by 2.
Multiply equation B by 3.
Multiply equation A by −3.
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OpenStudy (ccchristian1):
@geerky42
OpenStudy (ccchristian1):
@pooja195
jimthompson5910 (jim_thompson5910):
Fill in the box
\[\Large \boxed{ \ ^ \ } \ d + 3d = 0d\]
OpenStudy (ccchristian1):
whats the answer
jimthompson5910 (jim_thompson5910):
any ideas of what might go in there?
something plus 3d gives 0d
what is that "something" ?
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OpenStudy (ccchristian1):
b?
jimthompson5910 (jim_thompson5910):
b plus 3d = 0d ?
OpenStudy (ccchristian1):
no the answer
OpenStudy (ccchristian1):
i thik its b or c
OpenStudy (ccchristian1):
what dou think?
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jimthompson5910 (jim_thompson5910):
ok why not try this out
fill in the blank
\[\Large \underline{ \ \ \ \ \ } + 3 = 0\]
what goes in the blank?
OpenStudy (ccchristian1):
-3
jimthompson5910 (jim_thompson5910):
so that applies to the 3d as well
jimthompson5910 (jim_thompson5910):
-3d + 3d = 0d
jimthompson5910 (jim_thompson5910):
|dw:1434769362551:dw|
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OpenStudy (ccchristian1):
so the answer is D?
jimthompson5910 (jim_thompson5910):
|dw:1434769369508:dw|
OpenStudy (anonymous):
Multiply equation A by −3
jimthompson5910 (jim_thompson5910):
how do we turn that "d" in equation A into -3d ?
OpenStudy (ccchristian1):
thank you.
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