two planes left an airport at noon, one flew east and the other flew west at twice the speed. After 3 hours the planes were 2700mi apart. How fast was each plane flying?

Question

michele_laino · Answer

I call with v_A and v_B the velocities of each plane say plane A and plane B, furthermore, be:
v_B=2*v_A
then we can write:
$$\Large  d = {v_A}t + {v_B}t = {v_A}t + 2{v_A}t = 3{v_A}t$$
where t is the time namely t= 3 hours, and d is their separation, namely d= 2,700 mi
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michele_laino · Answer

so, substituting your data we get:
$$\Large 2700 = 3{v_A} \times 3$$
please solve for v_A

anonymous · Answer

wait what?

anonymous · Answer

can u explain please

michele_laino · Answer

we have:
$$\Large 2700 = 9{v_A}$$

michele_laino · Answer

now, please divide both sides by 9, what do you get?

michele_laino · Answer

hint:
|dw:1434807331602:dw|
what is v_A?