Question

two planes left an airport at noon, one flew east and the other flew west at twice the speed. After 3 hours the planes were 2700mi apart. How fast was each plane flying?

Answer 1

I call with v_A and v_B the velocities of each plane say plane A and plane B, furthermore, be:
v_B=2*v_A
then we can write:
\[\Large d = {v_A}t + {v_B}t = {v_A}t + 2{v_A}t = 3{v_A}t\]
where t is the time namely t= 3 hours, and d is their separation, namely d= 2,700 mi

Answer 2

so, substituting your data we get:
\[\Large 2700 = 3{v_A} \times 3\]
please solve for v_A

Answer 3

wait what?

Answer 4

can u explain please

Answer 5

we have:
\[\Large 2700 = 9{v_A}\]

Answer 6

now, please divide both sides by 9, what do you get?

Answer 7

hint:

what is v_A?