Question

Solve for x.

−ax + 3b > 5

x > the quantity 3 times b minus 5 all over a

x > the quantity 5 minus 3 times b all over negative a

x < the quantity 3 times b plus 5 all over a

x < the quantity negative 3 times b plus 5 all over negative a

Answer 1

1. First subtract 3b over to other side.

2. Divide by -a to change inequality sign to opposite since -a is negative.

3. Answer: \[-ax+3b>5\rightarrow -ax>5-3b \rightarrow x<(5-3b)/(-a)\]