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A line passes through the point (0, –1) and has a slope of -2/3. What is the equation of the line? a y=-2/3x-1 b y=3/2x+1 c y=2/3x+1 d y=-2/3x+1
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are you familiar with the point-slope form of the line formula?
y-y1 = m * (x-x1) where y1 and x1 are points.
i think i got it
the answer y=-2/3x-1
y-(-1)=-2/3(x-0) y+1=-2/3x y=-2/3x-1
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