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A marble is flicked horizontally off a desk with a speed of 3.1 m/s. If it takes the marble 0.8 seconds to hit the ground, how far from the desk does it land?
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Since the horizontal velocity of the marble is constant (there is no horizontal component for the acceleration), the horizontal distance achieved by the marble can be found using: \(d=v_0t\) you just need to plug in the initial velocity and the time given in the problem
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