Two boats start their journey from the same point A and travel along directions AC and AD, as shown below
What is the distance, CD, between the boats?
230.9 ft
284.3 ft
115.5 ft
173.2 ft
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OpenStudy (anonymous):
OpenStudy (anonymous):
@jigglypuff314 please help :)
jigglypuff314 (jigglypuff314):
|dw:1435073326407:dw|
jigglypuff314 (jigglypuff314):
remember these ratios? :)
OpenStudy (anonymous):
yeah thats given for a 30 60 90
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jigglypuff314 (jigglypuff314):
CD = BD - BC
so let's first try to find BC
OpenStudy (anonymous):
so BC = BD - CD
jigglypuff314 (jigglypuff314):
mm that was just to point out that to find CD (the answer)
we should try finding BC and BD using what we know about triangles :)
jigglypuff314 (jigglypuff314):
200 sqrt(3)
----- = ----------
BC 1
OpenStudy (anonymous):
so would you cross multiply...? I hate this chapter I'm sorry
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jigglypuff314 (jigglypuff314):
yes! cross multiply it :)
OpenStudy (anonymous):
200 = (BC)(sqrt3)
jigglypuff314 (jigglypuff314):
yes, now divide both sides by sqrt(3)
OpenStudy (anonymous):
115.47 = BC
jigglypuff314 (jigglypuff314):
that's right! :)
now, let's try to find BD
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OpenStudy (anonymous):
how would i start that
jigglypuff314 (jigglypuff314):
compare the my drawing to the given picture :)
the 200 is where the "x" is right?
and BD is where the "x sqrt(3)" is
jigglypuff314 (jigglypuff314):
since we are doing proportions, x is 1
so 200 1
------ = ---------
BD sqrt(3)
OpenStudy (anonymous):
BD = 346.4
jigglypuff314 (jigglypuff314):
good! now CD = BD - BC
so subtract the two numbers we got :)
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