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Solve this quadratic equation using the quadratic formula. 3x2 + 5x + 1 = 0
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list your abc values consider: \[ax^2+bx+c=0\]
\[\frac{ -5\pm \sqrt{5^{2}-4(3)(1)} }{ 2(3) }\]
Correct, now just simplify that.
\[\frac{ -5\pm \sqrt{13} }{ 6 }\]
Correct
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Good job :)
x = (-5 +/- 3.6) / 6 x = (-5 - 3.6)/6 or x = (-5 + 3.6)/6 x = -8.6/6 or x = -1.4/6 x = -1.43 or x = -0.23
ur welcome
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