Question

for \(1 10 years ago

Answer 1

easier to show \[x^2-3x+2\ge-\frac{1}{4}\]

Answer 2

i think i tried that

Answer 3

\(1<x<2 \Longrightarrow -2<x-3<-1 \Longrightarrow -2x<x^2-3x<-x \)
\(-2x+2<x^2-3x+2<-x+2 \)