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Mathematics 18 Online
OpenStudy (trojanpoem):

Prove that: [(2n+1)C(0)]^2 - [(2n+1)C(1)]^2 + [(2n+1)C(2)]^2 -..... - ([(2n+1)C(2n+1)]^2 = 0

OpenStudy (trojanpoem):

Someone rewrite it with EQN I can't.

OpenStudy (dan815):

like thsi right?

OpenStudy (dan815):

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