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OpenStudy (anonymous):
Radius OA of circle O has a slope of 2.5. What is the slope of the line tangent to circle O at point A?
0.8
2.5
-0.4
-5
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OpenStudy (amoodarya):
|dw:14351729953:dw
OpenStudy (amoodarya):
|dw:1435173081679:dw|
\[\frac{HA}{oH}=2.5\]
is this ? what you mean ?
OpenStudy (anonymous):
um i guess...it's cause the problem doesn't include a picture
OpenStudy (amoodarya):
|dw:1435173229389:dw|
OpenStudy (amoodarya):
you can draw an image (it help you to better understanding)
slope (oA) , slope(tangent line) =-1
because they are perpendicular
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OpenStudy (amoodarya):
now you must guess the answer !
can't you ?
OpenStudy (anonymous):
i dont know! i honestly dont know /:
OpenStudy (amoodarya):
if two line are perpendicular ...with slope \[m_1 ,m_2\]
so relation between them is :
\[m_1.m_2=-1\\m_1=2.5\\so\\m_2=?\]
OpenStudy (amoodarya):
m2 =?
OpenStudy (anonymous):
-3.5? idk!
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OpenStudy (amoodarya):
\[2.5 *m_2=-1\\m_2=\frac{-1}{2.5}=\frac{-1}{\frac{5}{2}}\\=\frac{-2}{5}\]
OpenStudy (anonymous):
-0.4
OpenStudy (amoodarya):
bravo
OpenStudy (anonymous):
yaaay! thank you!
OpenStudy (amoodarya):
understand ?
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OpenStudy (anonymous):
yes (:
OpenStudy (amoodarya):
it is not better to change your Id to igetmath ?
OpenStudy (anonymous):
you dont like my id name? lol
OpenStudy (amoodarya):
i live mathematics
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