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Mathematics 13 Online
OpenStudy (anonymous):

What is the solution set for this linear-quadratic system of equations? y = x2 − x − 12 y − x − 3 = 0 {(-3, 0), (0, 3)} {(-3, 0), (4, 0)} {(-3, 0), (5, 8)} {(4, 0), (0, 3)}

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