Question

Use the following scenario to answer the question:
A bag contains 5 green marbles, 4 red marbles, 7 blue marbles, and 9 yellow marbles.

If 3 marbles are drawn from the bag one at a time and not replaced, what is the probability of drawing a blue, yellow, and red marble in that particular order?
Select one:
a. equation
b. equation
c. equation
d. equation

Answer 1

There are 25 marbles in the bag. The probability of drawing a blue marble first is 7/25. Having drawn a blue marble there are 24 marbles left, and the probability of drawing a yellow marble second is 9/24. Now there are 23 marbles and the probability of drawing a red marble next is 4/23. The required probability is therefore the product of the three values of probability:
\[\large P(blue,\ yellow,\ red)=\frac{7\times9\times4}{25\times24\times23}\]

Answer 2

a. 1/48
b. 5/18
c. 21/1150
d. 6/11
these are fraction i just cant write them like fractions

Answer 3

The result that I gave you can be simplified to give one of the choices. Can you try to simplify.