Question

anyone from CA with ALg 2. B

Answer 1

simplify the trignometic expression:
sin^2theta/1+costheta

Answer 2

1.) sin(theta)+cos(theta)cot(theta)
----
sin(x) + cos(x*(cos/sin)
----
= (sin^2(x) + cos^2(x))/sin(x) = 1/sin(x) = csc(x)
=======================================================
2.)cos^2(theta)+tan^2(theta)cos^2(theta)
----
cos^2(x) + [sin^2(x)/cos^2(x)*cos^2(x)]
----
= cos^2(x) + sin^2(x)
-----
= 1

Answer 3

i dont have that in my answer choices: Ill show you
a. cos theta
b 1 + cos theta
c. 1 - cos theta
d. 1 - cos theta/ cos thetta

Answer 4

ok ill try and solve that

Answer 5

okay thanks

Answer 6

im still checking the answer but it might be A
but im not positive yet so dont put that

Answer 7

ok where are you checing the answer

Answer 8

what type of math is this exactly

Answer 9

i mean like is it trigonometry