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What is the radius of the circle whose equation is x(squared) + y(squared) = 8? A.) 2√2 B.) 4 C.) 64
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@peachpi
\[\large (x-h)^{2}~+~(y-k)^{2}=r^{2}\] \[\large (h,k)~=~Center~coordinates~of~circle\] \[\large r~=~radius\]
the "8" represents radius squared... you need to take sqrt of 8
@dumbcow I got 2√2
correct
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