Question

Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2, solve for g(f(3)).

Please help I'm so bad at algebra 2

Answer 1

g(x) = (3x - 1) / 2
f(x) = 2x + 1

start inside out for g(f(3))
f(3) = 2(3) + 1
f(3) = 7

g(f(3)) = (3(7) - 1) / 2
g(f(3)) = (21 - 1) / 2
g(f(3)) = 10

Answer 2

Thank you so much!!!!