when solving the rational equation -1/x-3=2x/x-3 you find that the solutions are -1/2 and 3. However, 3 is an extraneous solution. Why? A. There can only be one solution. B. The denominators can't be zero. C. The rational expressions will be zero. D. There was an error in the calculations

Question

when solving the rational equation -1/x-3=2x/x-3 you find that the solutions are -1/2 and 3. However, 3 is an extraneous solution. Why? A. 	 There can only be one solution.      B. 	 The denominators can't be zero. C. 	 The rational expressions will be zero. D. 	 There was an error in the calculations

anonymous · Answer

Can you divide by 0?

anonymous · Answer

I really dont think you can O.o

anonymous · Answer

If you can't divide by 0, 
"The denominators can't be zero"

anonymous · Answer

Fair enough :) Thank you