Question

Eight million (8,000,000) kg of water are at the verge of dropping over Niagara Falls to the rocks 50.0 meters below. What is the change in gravitational potential energy as the water splashes on the rocks below?

Answer 1

\[\Delta PE=mg(h_2-h_1)\]

Answer 2

h_2 = 0 m
h_1 = 50 m

Answer 3

8 million*50*9.81

Answer 4

basically, but you should probably go with the -50 since it's losing potential energy

Answer 5

ok