Question

please help

Answer 1

@jim_thompson5910

Answer 2

Help with what though?

Answer 3

jim_thompson5910 is helping me through message but he needed to see these images

Answer 4

I need help with this though

Find the area of the triangle.

24 square units
11 square units
12 square units
5.5 square units

Answer 5

Area of a triangle is \[\large A=\frac{1}{2}\times height \times base\] The base is going to be the distance between the two bottom points. The height will be the distance between the middle of the base and the top point.

Answer 6

so the base would be 6?

Answer 7

Correct.

Answer 8

and 5 for height?

Answer 9

so 15?

Answer 10

Close, it would be 4

Answer 11

oops okay thanku!

Answer 12

\[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]

Answer 13

this is for the 4 circles image
A point in the figure is selected at random. Find the probability that the point will be in the part that is NOT shaded.

Answer 14

@LegendarySadist

Answer 15

Do they give you any units, or no?

Answer 16

@jim_thompson5910

Answer 17

no

Answer 18

Well as we can see, the lengths of 2 diameters is the same as the length as one side of the square. If we say that the length of the side of the square is 4, then that means that the diameter of a circle is 1/4th that, or 1. Can you figure out the areas from that?

Answer 19

Im confused with this one too, i keep getting an answer thats not on my multiple choice

Find the area of the kite.

190.44 m2
126.96 m2
253.92 m2
380.88 m2

Answer 20

multiply the diagonals, then divide by 2

Answer 21

the diagonal lengths are given in pieces, so you'll have to add them up first

Answer 22

so theres 4 sides to a square 4+4+4+4= 16 and 16/ 1/4= 64
did i do it right?

Answer 23

@jim_thompson5910 all 4 of them?

Answer 24

the longer diagonal is 6.9+13.8 = 20.7

Answer 25

do the same for the other diagonal

multiply the diagonals, then divide by 2

Answer 26

so 6.9+13.8= 20.7
9.2+9.2= 18 2/5

Answer 27

my calc isnt letting me put in 2/5 after 18

Answer 28

ok its 380.88/2 = 190 11/25

Answer 29

so 190.44 m2 ?

Answer 30

@LegendarySadist so theres 4 sides to a square 4+4+4+4= 16 and 16/ 1/4= 64
did i do it right?

Answer 31

Area of a square is \[\large A=side^{2}\] and area of a circle is \[\large A=\pi r^{2}\]

Answer 32

so \[4^{2} + 4^{2} + 4^{2} + 4^{2} = 64 ?\]

Answer 33

Where are the 4 squares that you're adding together? What? It's JUST \(4^{2}\)

Answer 34

\[\large 4^{2}=16\] Boom, now we have the area of the square.

Answer 35

\[4^{2}= 16\]

Answer 36

oops

Answer 37

\[16\div \frac{ 1 }{ 4 } = 64\]

Answer 38

Now we find the area of the circle and multiply it by 4. Area of a circle is \(A=\pi r^{2}\) so if we want that times 4 it would look like \[\large A=4\pi r^{2}\] and HOW ARE YOU GETTING 64????

Answer 39

u said the diameter of a circle is 1/4th that? above^

Answer 40

sorry got confused.. what do i put for r?

Answer 41

so 4*3.14*5^2 = 314 could i do that or?

Answer 42

So the diamater of two circles is the side length. So \[\large 2d=side\] Since the radius is half of the diamater, it would be \[\large 4r=side\] The side is 4, as we know, so it would be \[\large 4r=4\] which makes \[\large r=1\]

Answer 43

so 4*3.14*1^2 = 12 14/25

Answer 44

Yeah. Now to find the area of the unshaded region, just do \[\large Area~of~square~~-~~Area~of~circles~=~Area~of~unshaded~region\]

Answer 45

so 16-12 14/25= 86/25

Answer 46

so 25%? or?

Answer 47

To find the chance of getting the unshaded region, so \[\large \frac{Area~of~Unshaded~region}{Area~of~square}\]

Answer 48

\[\frac{ 86 }{ 25 } \div 16 = \frac{ 43 }{ 200 }\]

Answer 49

thats not on my answers though..

Answer 50

In percentage form, it's 21.5% tho

Answer 51

yeah in decimal form its 0.215 so i guess i got confused

Answer 52

should of converted the decimal to percentage oops

Answer 53

thank you!

Answer 54

\[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]