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OpenStudy (anonymous):
Simplify- will medal and fan
(−2⋅qp^3)^3
Select one:
a.
m^3⋅p^12⋅q^6
b.
27⋅q^3⋅p^9
c.
4⋅m^8⋅p^6⋅q^8
d.
−8⋅q^3⋅p^9
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OpenStudy (campbell_st):
the external power of 3 operates on each part inside the brackets
\[(-2)^3 \times (p)^3 \times (q^3)^3\]
OpenStudy (campbell_st):
you should be able to simplify this
OpenStudy (anonymous):
@AWillie98 do you sill need help?
OpenStudy (anonymous):
yes @Miss.SweetiePie
OpenStudy (anonymous):
\[(-2)^{3}= -2 \times -2 \times -2 = -8\]
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OpenStudy (anonymous):
\[(p)^{3}=p ^{3}\]
OpenStudy (anonymous):
\[(q ^{3})^{3}=q ^{9}\]
OpenStudy (anonymous):
which gives you D
OpenStudy (anonymous):
thank you @Miss.SweetiePie
OpenStudy (anonymous):
any time
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OpenStudy (campbell_st):
nice thing about this site, if you wait long enough someone always give the answer
OpenStudy (anonymous):
@campbell_st who are you talking about????
OpenStudy (campbell_st):
the mantra of open study.... help improve understanding and don't give answers
OpenStudy (campbell_st):
@annas, perhaps the question was to difficult for open study
OpenStudy (campbell_st):
I choose to help for free... and many do... that way I can pick and choose... @annas
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