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Solve: -6 is less then or equal to 2x+1/4 is less then or equal to 6.
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\[0\le x \le \frac{ -1 }{ 8 }\]
\[-6\le 2x+\frac{ 1 }{ 4 }\le 6\]\[0\le6+2x+\frac{ 1 }{ 4 }-6\le0\]\[0\le2x+\frac{ 1 }{ 4 }\le0\]\[0lex \le \frac{ -1 }{ 4 }\]\[0\le x \le \frac{ -1 }{ 8 }\]
the second to last shd be \[0\le 2x \le \frac{ -1 }{ 4 }\]
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