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Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x minus three, over two, solve for f(g(x)) when x = 1.
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Answers: -1 0 3 4
please help guys
f(g(x)) at x = 1 means find g(x) when x = 1, then take that value and substitute for x in f(x)
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or, put another way, f(g(x)) = g(x)^2 + 3(g(x)) + 6 when x = 1
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