Question

n^3+5n^2-4n-20

Answer 1

\[n ^{3}+5n ^{2}-4n-20\]

Answer 2

\[n ^{2}(n+5)-4(n+5)\]

Answer 3

\[(n ^{2}-4)(n+5)\]

Answer 4

Do you understand so far?

Answer 5

if you need to solve for n we take each bracket and let it =0 then solve for n ok

Answer 6

this could either be solve for n or factor by grouping. The question is too general.

Answer 7

@mommy_ hi was your question solve for n or factor by grouping ?

Answer 8

Yeah thanks