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HELP! (11-2)! 4!- ------- 8!
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Can someone explain with steps?!
we have the subsequent steps: \[\large \left( {4!} \right) \times \frac{{\left( {11 - 2} \right)!}}{{8!}} = 24 \times \frac{{9!}}{{8!}} = 24 \times \frac{{\left( {8!} \right) \times 9}}{{\left( {8!} \right)}} = 24 \times 9 = ...\]
since: n! = (n-1)!*n
and: 4!=4*3*2*1= 24
Thank you!
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