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Just wanna make sure that I got this right: Quadrilateral BCDE is inscribed inside a circle as shown below. Write a proof showing that angles C and E are supplementary. My answer: In BCD: BCD + CBD + CDB = 180 degrees The inscribed angles are congruent so: CBD = CED CDB = CEB By Substitution: BCD + CED + CEB = 180 degrees By angle addition postulate : angle C + angle E = 180 degrees
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This is the picture:
@ParthKohli Could you please help me out here? :)
That's all correct. well done!
I've checked the detail and it's all fine
It's too bad that no-one has helped you out before
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Thank you very much :)
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