Question

Find the equation of the line that passes through (-6, 5) with a slope of (minus 2 over 3 ).

Answer 1

You are already given m = -2/3

So equation would looks like \(y = \text-\dfrac23x+b\)

We need to solve for y-intercept. So since we are given that it passes point \((\text-6,5)\), we can plug in \(x = \text-6\) and \(y=5\), then solve for \(b\);

\(5 = \text-\dfrac23(\text-6)+b\)

Solve for b.