Question

Help pleasee

Answer 1

Simplify. (x+3)^2

Answer 2

x^2+6?

Answer 3

or 2x^2+6

Answer 4

You are squaring something 3^2 = ?

Answer 5

9

Answer 6

so 3^2=9

Answer 7

YUP!!!!!

So your equation goes something along the lines of x^2 +/- x +/- # = 0 Fill in the blanks.

Answer 8

no its not

Answer 9

x^2-4x+9=0 ?

Answer 10

Simplify (x+3)2 + 4x
Evaluate : (x+3)2 = x2+6x+9
Factoring x2+10x+9
(x+9) • (x+1)
(x + 9) • (x + 1) = 0
Solve (x+9)•(x+1) = 0
Solve : x+9 = 0
Subtract 9 from both sides of the equation :
x = -9
Solve : x+1 = 0

Subtract 1 from both sides of the equation :
x = -1

Answer 11

No. you're not moving anything across an equal sign. so there's no need to change the postive and negative.

x^2 + 4x + 9

Answer 12

@Albany_Goon The question isn't asking us to find "x". It's asking us to rearrange the equation.

Answer 13

ok so then its 0

Answer 14

because she has to write the cubic polynomial on the left hand side in standard form rite?

Answer 15

x^2-4x+9=0 ? is this correct?

Answer 16

@zarkam21 No, not quite. you seem to have the -4x wrong. It should be

\[x^2+4x+9 = 0\]

Answer 17

Thanks @sloppycanada