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If y varies directly as x, and y = 15 as x = -3, find y for the x-value of 4. The answer is 2 If y varies inversely as x, and y = 5 as x = 6, find y for the x-value of 10. k = 60?
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@Loser66 Just making sure these answers are correct.
Nope. y =15, x =-3, hence k =-5, your equation is y = -5x, then if x =4, y = -20, not 2
if y is varies inversely as x, that is y = k/x , k/x = 5 when x =6, hence k = 30 , not 60 y = 30/x, if x =10 , y = 3 hey!! I worked!!! not you. why???
I honestly didn't think I could plug in the new numbers into the first solution..
\(y =kx\\15 = k*(-3)\\k = \dfrac{15}{-3}=-5\)
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hence \(y = (-5)x\)
Now, find y if x =4, just replace x =4 into it \(y = (-5)*4= -20\)
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