Question

City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was −3° C. What was the temperature of City A and City B on that day?

Answer 1

City A was 5° C, and City B was 4° C.
City A was 3° C, and City B was −1° C.
City A was 8° C, and City B was −3° C.
City A was 5° C, and City B was −5° C

Answer 2

would it be the second answer

Answer 3

let temperature in CitY A be x and temperature in City B be y

Answer 4

4x = 3x + 8
x - 2y = -3

Answer 5

wait so why would it be 4x instead of 8x

Answer 6

you can find which option is correct by plugging in the given values and see which ones fit

Answer 7

4 times x = 4x

Answer 8

four times the temperature of city A = 4 times x = 4x

Answer 9

ok thank you that makes alot more sense

Answer 10

you can solve the system of equations or as I said earlier you can plug in the values in the options to see which fit.

Answer 11

ill plug in the values

Answer 12

4(3)=3(3)+8

Answer 13

first try x=5 and y = 4
4(5) = 3(4) + 8
20 = 12 + 8
- those fit

Answer 14

now plug same values into
x - 2y = -3

Answer 15

ok gotcha

Answer 16

(5)-2(4)=-3

Answer 17

5-8=-3
-3=-3

Answer 18

it works

Answer 19

right

Answer 20

thanks