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Mathematics 8 Online
OpenStudy (anonymous):

An office has 6 employees; there are 5 female employees and 1 male employee. In how many ways can a 3 person committee be created if the committee must include the male employee?

OpenStudy (welshfella):

you need 2 female employees to make up the committee of 3. this = 5C2 - the number of combination of 2 in 5

OpenStudy (anonymous):

y isnt it permutations? 4 x 3 x 1

OpenStudy (welshfella):

can you calculate 5C2?

OpenStudy (anonymous):

yes it's 10 but how come it's not permutations i thought the order matters here

OpenStudy (welshfella):

the order doesn't matter in this case

OpenStudy (anonymous):

y

OpenStudy (welshfella):

yes 5*4 /2 = 10 is correct

OpenStudy (anonymous):

y doesn't the order matter?

OpenStudy (welshfella):

well Jane , Lois and Jack are the same committee as Lois, Jane and Jack

OpenStudy (anonymous):

huh

OpenStudy (welshfella):

that-s a committee - 3 people the order they are picked doesn't matter

OpenStudy (anonymous):

So you're saying that because the guy is gonna be in the committee anyway it doesn't matter?

OpenStudy (welshfella):

is Jack, Lois and Jane a different committee to Lois Jane and Jack?

OpenStudy (anonymous):

no

OpenStudy (welshfella):

there you go then

OpenStudy (anonymous):

still no clue

OpenStudy (anonymous):

still think 4 x 3 x 1 is supposed to be right

OpenStudy (welshfella):

why 4*3*1 ?

OpenStudy (anonymous):

permutations no?

OpenStudy (anonymous):

wait nvm i got it thanks

OpenStudy (welshfella):

ok

OpenStudy (welshfella):

you can write all the different combinations of 2 from 5 if you like - the man is always there so if the females are a,b,c,d and e then combinations are ab ac ad ae bc bd be cd ce de which are 10

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