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Mathematics 9 Online
OpenStudy (hellokitty17):

Factor completely 4x3 + 28x2 + 7x + 49. (x − 7)(4x2 + 7) (x − 7)(4x2 − 7) (x + 7)(4x2 + 7) (x + 7)(4x2 − 7)

oregonduck (oregonduck):

@paki

oregonduck (oregonduck):

C) (x + 7)(4x^2 + 7)

OpenStudy (mathmate):

Hint: Rewrite \(4x^3 + 28x^2 + 7x + 49.\) as \(4x^2(x +7) + 7(x + 7)\) and then factor out the common factor (x+7).

OpenStudy (hellokitty17):

thanks @OregonDuck

oregonduck (oregonduck):

yup anytime :)

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