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Use the function below to fine F(-2) F(x)=3^x A.1/6 B.1/9 C.-9 D.-6
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\(\huge a^{-b}=\dfrac{1}{a^b}\)
`Step 1`: you have to plug in -2 instead of x, into the function (that is, into 3\(^x\)) `Step 2`: Evaluate the expression, you have (after plugging in 2 for x), using the rule that @jenny1994 wrote out for you. `Step 3`: Lastly, (simplify the result, if there is anything to simplfy).
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