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Mathematics 18 Online
OpenStudy (anonymous):

Please help! Fan and Medal! Consider the graph of f(x) below. https://wca.sooschools.com/media/g_alg02_ccss_2014/9/img_g_alg02u09c03l20d_03.gif Write the equation of f(x), and classify the function as linear, quadratic, cubic, exponential, or logarithmic.

OpenStudy (sloppycanada):

First step - finding out what type of graph it is. Can we eliminate any of them?

OpenStudy (anonymous):

Its deffinitely not linear or exponential @sloppycanada

OpenStudy (anonymous):

I think its cubic

OpenStudy (sloppycanada):

Can you give me a reason as to why it would be logarithmic?

OpenStudy (anonymous):

I really dont know @sloppycanada

OpenStudy (anonymous):

ik this ill help

OpenStudy (loser66):

with that shape, it is ALWAYS a cubic

OpenStudy (loser66):

with the positive coefficient of x^3

OpenStudy (loser66):

Hence, the standard formula is \(f(x) =ax^3+bx^2+cx +d\)

OpenStudy (loser66):

All you need is picking 4 special points to plug into the standard form. Hint: pick x -intercept and y intercept points

OpenStudy (anonymous):

gtfo loser you can help nobody

OpenStudy (loser66):

I do one for you as example:

OpenStudy (anonymous):

do you have a calculator?

OpenStudy (anonymous):

Madison.bush ?

OpenStudy (anonymous):

its not linear

OpenStudy (loser66):

the first x-intercept is (-1,0) , that is x =-1, y =0 hence plug in, you have \(0= a(-1)^3 +b*(-1)^2+c(-1) +d\)

OpenStudy (anonymous):

Yes i do have a calculator @adriangomez

OpenStudy (anonymous):

so it is cubic

OpenStudy (anonymous):

we just need to find a equation im i correct

OpenStudy (loser66):

Do the same with other points to get 4 equations and solve for a, b, c , d Btw, calculator is helpless here. No way to find the equation of it by calculator.

OpenStudy (anonymous):

Okay thank you @Loser66

OpenStudy (anonymous):

just put the numbers in and trace it @madison.bush

OpenStudy (anonymous):

on calculator

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