Question

The equation of a circle whose center is at ( 4,0 ) and radius is length 2 ( square root ) 3

Answer 1

\[(x-h)^2+(y-k)^2=r^2 \\ \text{ has center } (h,k) \\ \text{ and radius } r\]

Answer 2

your center is given has (4,0)=(h,k)
this tells you to replace h with 4
and k with 0

you are also given radius
which is called r above
so replace r with whatever number it is you have there 2sqrt(3)?

Answer 3

Ohhhh okay