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In this triangle, the product of sin B and tan C is , and the product of sin C and tan B is . NextReset
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got formula right?
no
sin B = b/a
tan (B) = b/c
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is it correct?
i have to see
i think got formula
for first question the product of sin B and tan C : hence sin B x tan C =b/a x c/b
u can refer the graph that i draw..
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this is the formula : SOH... Sine: sin(θ) = Opposite / Hypotenuse ...CAH... Cosine: cos(θ) = Adjacent / Hypotenuse ...TOA Tangent: tan(θ) = Opposite / Adjacent
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