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Geometry 9 Online
OpenStudy (anonymous):

In this triangle, the product of sin B and tan C is , and the product of sin C and tan B is . NextReset

OpenStudy (anonymous):

OpenStudy (anonymous):

got formula right?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

sin B = b/a

OpenStudy (anonymous):

tan (B) = b/c

OpenStudy (anonymous):

is it correct?

OpenStudy (anonymous):

i have to see

OpenStudy (anonymous):

i think got formula

OpenStudy (anonymous):

for first question the product of sin B and tan C : hence sin B x tan C =b/a x c/b

OpenStudy (anonymous):

u can refer the graph that i draw..

OpenStudy (anonymous):

this is the formula : SOH... Sine: sin(θ) = Opposite / Hypotenuse ...CAH... Cosine: cos(θ) = Adjacent / Hypotenuse ...TOA Tangent: tan(θ) = Opposite / Adjacent

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