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Factor completely 10x2 + 2x – 8. 2(5x - 1)(x + 4) 2(5x - 4)(x + 1) 2(5x + 2)(x - 2) 2(5x - 2)(x + 2)
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do you know the greatest common factor of 10,2,8?
2
great so when you factor out 2 you have \[10x^2+2x-8 \\ 2(5)x^2+2(1)x-2(4) \\ 2(5x^2+1x-4)\] now let's look at factoring the thingy in ( ) That is let's look at factoring: \[5x^2+1x-4 \text{ aka } 5x^2+x-4\]
notice a=5 b=1 c=-4 you are looking for two factors of ac that have product ac and sum b
that is what two integer numbers when you multiply them give you -20 and when you add them give you 1
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2*(x+1)*(5x-4)
so b
Remember to not give direct answers in the future. Thank you kindly.
ok sorry
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