What is the relative maximum and minimum of the function?

f(x) = 2x^2 + 28x - 8

A. Minimum Value: -106 Range y -106
B.Minimum Value: -7 Range y -7
D.Minimum Value: 7 Range y 7

Question

What is the relative maximum and minimum of the function?

f(x) = 2x^2 + 28x - 8

A. Minimum Value: -106 Range y > -106
B.Minimum Value: -7 Range y > -7
D.Minimum Value: 7 Range y > 7

anonymous · Answer

@SolomonZelman

anonymous · Answer

$$f(x)=2x ^{2}+28x-8$$

solomonzelman · Answer

minimum is the vertex in this case.
(it doesn't have an abd max)

anonymous · Answer

how do i find the vertex? @SolomonZelman

decentnabeel · Answer

A. Minimum Value: -106 Range y > -106

anonymous · Answer

how did you find that? I am just wondering so I can try and solve similar equations in the future @DecentNabeel

decentnabeel · Answer

fist find the stationary..
$$\mathrm{Find\:the\:stationary\:points}:\quad x=-7$$

decentnabeel · Answer

then find the..
$$\mathrm{Find\:the\:monotone\:intervals}$$

decentnabeel · Answer

then..
$$\mathrm{Identify\:the\:extreme\:points}:\quad \mathrm{Minimum}\left(-7,\:-106\right)$$