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Mathematics 23 Online
OpenStudy (anonymous):

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the test: The 2nd period class should get the reward. They have the highest score, a perfect 100. The 2nd period class should get the reward. They have a higher median. The 4th period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd period class. The 4th period class should get the reward. Their lowest score is and should be thrown out

OpenStudy (anonymous):

OpenStudy (jennyrlz):

Well we are looking for which class as a accumulative force did better

OpenStudy (jennyrlz):

Meaning the it is not a

OpenStudy (anonymous):

ok, so D isnt it either, because it says to throw out an outlier

OpenStudy (jennyrlz):

Since we see that over all the second period class is overall ahead in the picture, leaving only one option :)

OpenStudy (jennyrlz):

Yup ^.^

OpenStudy (jennyrlz):

Meaning b and c, b is the answer because they do have the highest median :)

OpenStudy (anonymous):

ok, thank you :)

OpenStudy (jennyrlz):

They could have used the word mean (average) and it would've still been b

OpenStudy (jennyrlz):

No :)

OpenStudy (jennyrlz):

Np*

OpenStudy (jennyrlz):

Auto correct xD

OpenStudy (anonymous):

no, it would be C, because if its based on average, 4th period's q1 and q3 are higher than second's

OpenStudy (anonymous):

and the medians are the same

OpenStudy (jennyrlz):

Wait but... Well... I see... My bad :/

OpenStudy (jennyrlz):

But hey I am glad you found the answer

OpenStudy (jennyrlz):

I'll medal you :)

OpenStudy (anonymous):

thanks for the help

OpenStudy (jennyrlz):

Np, wish I could've been of more use :/

OpenStudy (anonymous):

its fine

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