What is the general form of the equation for the given circle?

x2 + y2 − 8x − 8y + 23 = 0

x2 + y2 − 8x − 8y + 32 = 0

x2 + y2 − 4x − 4y + 23 = 0

x2 + y2 + 4x + 4y + 9 = 0

Question

What is the general form of the equation for the given circle?

x2 + y2 − 8x − 8y + 23 = 0

x2 + y2 − 8x − 8y + 32 = 0

x2 + y2 − 4x − 4y + 23 = 0

x2 + y2 + 4x + 4y + 9 = 0

anonymous · Answer

idk how to put a pic on here so im just gonna describe the circle

anonymous · Answer

it's 90 degrees with points A (4,7) and B (7,4)

anonymous · Answer

please help!

anonymous · Answer

@Marcorie

anonymous · Answer

A) (x-4)^2 + (y-4)^2 = 3

anonymous · Answer

do i solve that or something?

anonymous · Answer

No i solved the first equation 
this is standard form for a circle

anonymous · Answer

(x-h)^2 + (y-h)^2 = r^2

xapproachesinfinity · Answer

you have to show how ? no direct answer are allowed in OP

anonymous · Answer

Okay sorry I'm new to this

anonymous · Answer

i dont have to show how i just need the answer @xapproachesinfinity

anonymous · Answer

(x-h)^2 + (y-h)^2 = r^2

anonymous · Answer

it's fine i just really need the answer @Deezzz

xapproachesinfinity · Answer

it is not allowed in open study!!

anonymous · Answer

where (h,k) is the center and r is the radius of the circle

anonymous · Answer

please just help!! i honestly dont care about the work i just really need the answer so i could pass this damn test

xapproachesinfinity · Answer

whether you just need the answer or not you have the follow the guide lines

anonymous · Answer

-.- @xapproachesinfinity

anonymous · Answer

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