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OpenStudy (anonymous):
Lim [(1/x-1)-(2/x^2-1)], x->1 Right answer is 1/2
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OpenStudy (freckles):
combine fractions
OpenStudy (anonymous):
\[\frac{1}{x-1}-\frac{2}{x^2-1}=\frac{1}{x+1} \]
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