Mathematics
20 Online
OpenStudy (anonymous):
HELP, PLEASE.
3(x-2)≤1/3 solve inequality
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
this is an "and" case
we can set up a 3 part inequality
OpenStudy (anonymous):
I am confused what you did there. Did you divide 1/3 to both sides?
OpenStudy (anonymous):
correct divide 3 by both sides
OpenStudy (anonymous):
what did you get
OpenStudy (anonymous):
3(x-2)/3 <=1/3 /3
Would I distribute first and then divide or just divide the whole thing?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
You distribute first
OpenStudy (anonymous):
I was thinkingg about absolute value sorry
OpenStudy (anonymous):
3x-6<=1/3
OpenStudy (anonymous):
add 6
OpenStudy (anonymous):
To both sides?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
or divide by 3
OpenStudy (anonymous):
3x<= 6 1/3
OpenStudy (anonymous):
yes what you do to one side you do to the other
OpenStudy (anonymous):
Then I would divide by three?
OpenStudy (anonymous):
6+1/3
18/3 +1/3
19/3
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
3x<== 19/3
x<== 19/9
OpenStudy (anonymous):
i got x 19/9
OpenStudy (anonymous):
Did you turn it into an improper fraction? I am unsure how you got 18/3 + 1/3
OpenStudy (anonymous):
* x==>19/9
OpenStudy (anonymous):
yes i turned 6 into an improper fraction
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
6= 18/3
OpenStudy (anonymous):
Okay so 19/3 <= X?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
x has to bes less than or equal to 19/9
OpenStudy (anonymous):
you forgot to divide it by 3
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Right, I was about to mention.
OpenStudy (anonymous):
So we have 3x => 6 1/3 divided by 3?
OpenStudy (anonymous):
so we get
x==> 2 1/9
OpenStudy (anonymous):
2 1/9 = 19/9
OpenStudy (anonymous):
Right, so X<= 19/9 or 2 1/9
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
no x==> 19/9
we did not divide by a negative to change the sign
OpenStudy (anonymous):
So X is greater than or equal to 19/9?
OpenStudy (anonymous):
\[x \le 19/9\]
OpenStudy (anonymous):
less than
OpenStudy (anonymous):
or equal to
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Okay, thanks a lot for walking me through it.
OpenStudy (anonymous):
no worries
OpenStudy (anonymous):
Could you help me verify my solution to using some of the numbers from the solution set?
OpenStudy (anonymous):
so it has to be less than 2 1/9 lets try 0 since its the easiest
OpenStudy (anonymous):
f(0) = 3(0-2)≤1/3
3(-2) ≤1/3
-6≤1/3
its checks out
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Awesome, thanks!