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Mathematics 9 Online
OpenStudy (anonymous):

help please

OpenStudy (anonymous):

OpenStudy (sloppycanada):

Sine Opposite Hypotenuse Cosine Adjacent Hypotenuse Tangent Opposite Adjacent

OpenStudy (anonymous):

Use the cosine law . And smarten up

OpenStudy (starwars18):

soh cah toa, so adjacent over hypotenuse, or 8/10

OpenStudy (amoodarya):

use cosine law ,as robert136 said :\[b^2+c^2-a^2=2bc \cos (A)\\8^2+10^2-7^2=2(10)(8)\cos (\theta)\] can you go on

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