Find the equation, in standard form, of the line passing through the points (3,-4) and (5,1).

Question

moazzam07 · Answer

First find the slope using equation %28y2+-+y1%29%2F%28x2+-+x1%29
Make (5,1) = (x1,y1)
(-2,3) = (x2,y2)
Substituting
%28y2+-+y1%29%2F%28x2+-+x1%29 = %283+-+1%29%2F%28-2+-+5%29=%282%29%2F%28-7%29
Now use y = mx + b as a template. m = %282%29%2F%28-7%29 as just determined.

 
for y and x, use the point (5,1). x=5 and y =1.
Substitute these values in y = mx + b
y = mx + b ; 1 = (-2/7)5 + b
1 = -10/7 + b
add 10/7 to each side
1 + 10/7 = b
17/7 = b
So our equation is y = (-2/7)x + 17/7

moazzam07 · Answer

you can do it the same way but with your problem

anonymous · Answer

$$5 x-2 y=23 $$"Find the equation, in standard form . . ."