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f(x)= c^2 +7x if x<4. f(x)= x^3-cx if x>/=4. What is C?
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\[f(x)= cx ^{2}+7x \rightarrow x<4\] \[f(x)=x ^{3}-Cx \rightarrow x \ge 4\]
plug in the 4, then set the 2 pieces of the function equal to solve for c
\[16c+28=64-4c\]
Continuous on \[\left( -\infty, \infty\right)\] ?
that's how you would make f(x) continuous, by making the 2 pieces equal at 4
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