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Trigonometry 18 Online
OpenStudy (anonymous):

ALGEBRA 2 WILL GIVE MEDAL

OpenStudy (anonymous):

What are the amplitude, period, and midline of the function? Amplitude: 4; period: 2π; midline: y = −1 Amplitude: 8; period: 2π; midline: y = 1 Amplitude: 8; period: π; midline: y = −1 Amplitude: 4; period: π; midline: y = 1

OpenStudy (anonymous):

Use graph

OpenStudy (anonymous):

Amplitude is half of the distance between the highest lowest points. The top and bottom points are 3 and -5, respectively. The distance between is 8, so the amplitude is half of 8, or 4.

OpenStudy (anonymous):

so b?

OpenStudy (anonymous):

First, we have to determine what the other 2 are. And second, B says that the amplitude is 8, so it can't be B.

OpenStudy (anonymous):

Oh ok so

OpenStudy (anonymous):

It will be A or D

OpenStudy (anonymous):

D

OpenStudy (anonymous):

Let's figure out what the period is. The period is the distance between the point on any wave and the same point on another wave. Kinda complicated way to say it, so a simpler way is just the distance between the tops of the waves. What is the horizontal difference between the top of two of the waves?

OpenStudy (anonymous):

4

OpenStudy (anonymous):

The distance of the red line in http://prntscr.com/7p9t23

OpenStudy (anonymous):

3

OpenStudy (anonymous):

Are you sure? Look at the number on the line.

OpenStudy (anonymous):

Its 4

OpenStudy (anonymous):

The amplitude is 4, but we're talking about the period here

OpenStudy (anonymous):

Thats 3???

OpenStudy (anonymous):

OH

OpenStudy (anonymous):

Remember, it's horizontal distance, not vertical

OpenStudy (anonymous):

2!

OpenStudy (anonymous):

2 what? There's something after the 2.

OpenStudy (anonymous):

Pi

OpenStudy (anonymous):

Yeah, it's \(2\pi\) So it has amplitude of 4 and period of \(2\pi\). Which choice is that?

OpenStudy (anonymous):

A

OpenStudy (anonymous):

can u help me w a few more

OpenStudy (anonymous):

Correct :)

OpenStudy (anonymous):

Sure, I can help with a few more, just tag me in a separate question. :)

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